Show that cos 24 + cos 55 + cos 125 + cos 204 + cos 300= 1/2
(cos24+cos204)+(cos55 + cos125) +cos300 = 1/2
L.H.S.
= (2cos112cos90) + (2cos90cos35) + cos(360-60)
= (2cos112.0) + (2cos35.0) +cos60......[ bcoz cosx + cosy = 2cos(x+y)/2cos(x-y)/2 ] and [cos90 = 0]
= 0 + 0 + 1/2
= 1/2
= R.H.S.
hence prOved