The first 3 terms in the expansion of (1+ax)n are 1, 12x, 64x2respectively, Find n and 'a' - Maths - Binomial Theorem

Question

The first 3 terms in the expansion of (1+ax)n are 1,
12x, 64x2respectively, Find n and 'a'

Ankush Jain · Accepted Answer

Given, first 3 terms in the expansion of (1+ax)n are 1, 12x, 64x2 respectively â‡’

Now, na = 12 â‡’ 9a = 12 â‡’ a = 4/3

The first 3 terms in the expansion of (1+ax)n are 1, 12x, 64x2respectively, Find n and 'a' .